An ideal gas is taken through an isothermal process. If it does 2000 J of work on its environment, how much heat is added to it?
After going through the question, we can list some data as,
workdone dW = 2000J
isothermal process dU = 0
To find , Heat added dQ = ?
Solution –
From first law of thermodynamics we have
dQ = dU + dW
In the question it is given that the gas is taken through isothermal process, i.e the change in internal energy should be ZERO i.e dU =0
therefore, dQ = 0 + dW
dQ = dW = 2000J